A=\(\frac{\left(\frac{13}{84}.\frac{1}{4}-\frac{2}{5}.\frac{7}{180}\right):2\frac{7}{18}+4\frac{1}{2}.0.1}{70.5-528:7\frac{1}{2}}\)
\(\frac{\left(\frac{13}{84}.\frac{7}{5}-\frac{5}{2}.\frac{7}{180}\right):\frac{43}{18}+\frac{9}{2}.\frac{1}{10}}{\frac{141}{2}-528:\frac{15}{2}}\)
=\(\frac{\frac{43}{360}.\frac{18}{43}+\frac{9}{20}}{\frac{705-704}{10}}=\frac{\frac{1}{20}+\frac{9}{20}}{\frac{1}{10}}=\frac{1}{\frac{2}{\frac{1}{10}}}=\frac{1}{2}.10=5\)
thực hiện các phép tính sau
a) \(\frac{\left(\frac{13}{84}.1,4-2,5.\frac{7}{180}\right):2\frac{7}{18}+4\frac{1}{2}.0,1}{70,5-528:7\frac{1}{2}}\)
cần gấp !!!!!!!!!!!!!
Rút gọn biểu thức sau:
P=\(\frac{\left(\frac{13}{84}\times1,4-2,5\times\frac{7}{180}\right)\div2\frac{7}{18}+4\frac{1}{2}\times0,1}{70,7-528:\frac{7}{1}}\)
Giúp mình giải bài toán này nhé Cảm ơn các bạn rất nhiều
\(\frac{\left(\frac{13}{84}×1,4-2,5×\frac{7}{180}\right)\div2\frac{7}{18}+4\frac{1}{2}×0,1}{70,5-528\div7\frac{1}{2}}\)
Giúp mình giải bài toán về với nhé Cảm ơn các bạn rất nhiều( nhớ giải đầy đủ giúp mình nhé)
\(\frac{\left(\frac{13}{84}×1,4-2,5×\frac{7}{180}\right)\div2\frac{7}{18}+4\frac{1}{2}×0,1}{70,5-528\div7\frac{1}{2}}\)
\(\frac{\left(5\frac{4}{45}-4\frac{1}{15}\right)×30}{1\frac{1}{3}}-\frac{4,25\div0,85+1\div0,5}{\left(5,36-4,06\right)\div3-6,5}\)
Tính giá trị của biểu thức sau: P = \(\left(\frac{13}{84}\times1\frac{2}{5}-2\frac{1}{2}\times\frac{7}{180}\right)\div2\frac{7}{18}+4\frac{1}{2}\)\(\times\frac{1}{10}\)
P = \(\left(\frac{13}{84}\times1\frac{2}{5}-2\frac{1}{2}\times\frac{7}{180}\right):2\frac{7}{18}+4\frac{1}{2}\times\frac{1}{10}\)
P = ( 13/84 x 7/5 - 5/2 x 7/180 ) : 43/18 + 9/2 x 1/10
P = ( 13/60 - 7/72 ) : 43/18 + 9/20
P = 43/360 : 43/18 + 9/20
P = 43/360 x 18/43 + 9/20
P = 1/20 + 9/20
P = 1/2
Bạn bấm phân số và hỗn số như nào vậy!Chỉ cách giúp mình với.
tính:
\(\frac{\left(\frac{13}{24}.1,4-2,5.\frac{7}{180}\right):2\frac{7}{18}+4\frac{1}{2}.0,1}{70,5-528.7\frac{1}{2}}\)
cai nay ban cu tinh nhu binh thuong thoi
Tính giá trị biểu thức
\(1.A=\frac{1}{5}+\frac{3}{17}-\frac{4}{3}+\left(\frac{4}{5}-\frac{3}{17}+\frac{1}{3}\right)-\frac{1}{7}+\left[\frac{-14}{30}\right]\)
\(2.B=\left(\frac{5}{8}-\frac{4}{12}+\frac{3}{2}\right)-\left(\frac{5}{8}+\frac{9}{13}\right)-\left[\frac{-3}{2}\right]+\frac{7}{-15}\)
\(3.C=\frac{5}{18}+\frac{8}{19}-\frac{7}{21}+\left(\frac{-10}{36}+\frac{11}{19}+\frac{1}{3}\right)-\frac{5}{8}\)
\(4.D=\frac{1}{9}-\left[\frac{-5}{23}\right]-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{14}-\frac{7}{30}\)
\(5.E=\frac{1}{13}+\left(\frac{-5}{18}-\frac{1}{13}+\frac{12}{17}\right)+\left(\frac{12}{17}+\frac{5}{18}+\frac{7}{5}\right)\)
\(6.F=\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{12}{17}-\frac{15}{14}+\frac{1}{4}\right)\)
\(7.G=\frac{1}{25}-\frac{4}{27}+\left(\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}\right)+\frac{5}{43}-\frac{4}{7}\)
\(8.H=\frac{4}{15}-\frac{23}{28}-\left(\frac{-23}{28}+\frac{-11}{15}-\frac{29}{27}\right)-\frac{2}{27}\)
\(9.K=\frac{1}{16}-\frac{5}{21}+\left(\frac{-1}{16}+\frac{-3}{5}-\frac{-5}{21}\right)+\frac{-2}{5}+\frac{3}{4}\)
\(10.L=\frac{7}{12}+\frac{15}{14}-\left(\frac{14}{22}+\frac{-1}{14}+\frac{5}{21}\right)-\frac{-5}{21}+\frac{3}{5}\)
yutyugubhujyikiu
a,\(\frac{-1}{24}-\left[\frac{1}{4}-\left(\frac{1}{2}-\frac{7}{8}\right)\right]\)
b,\(\left[\frac{5}{7}-\frac{7}{5}\right]-\left[\frac{1}{2}-\left(\frac{-2}{7}-\frac{1}{10}\right)\right]\)
c,\(\left(\frac{-1}{2}\right)-\left(\frac{-3}{5}\right)+\left(\frac{-1}{9}\right)+\frac{1}{71}-\left(\frac{-2}{7}\right)+\frac{4}{35}-\frac{7}{8}\)
d,\(\left(3-\frac{1}{4}+\frac{2}{3}\right)-\left(5-\frac{1}{3}-\frac{6}{5}\right)-\left(6-\frac{7}{4}+\frac{3}{2}\right)\)
e,\(\left(\frac{1}{2}-\frac{13}{14}\right):\frac{5}{7}-\left(\frac{-2}{21}+\frac{1}{7}\right):\frac{5}{7}\)
g,\(\frac{4}{9}:\left(\frac{-1}{7}\right)+6\frac{5}{9}:\left(\frac{-1}{7}\right)\)